The time in air calculated with the equation of the upward vertical motion.Ĭhoose upward direction as positive and downward direction as negative. The x motion occurs at constant velocity and the y motion occurs at constant acceleration of gravity. Projectile motion could be understood by analyzing the horizontal and vertical component of the motion separately. The vertical component of the initial velocity : The horizontal component of the initial velocity : A kicked football leaves the ground at an angle θ = 45 o with the horizontal has an initial speed of 25 m/s. Acceleration due to gravity = 10 m/ s2, what is the time interval before the object hits the ground.Īcceleration due to gravity (g) = 10 m/s 2Ĥ. At the height of 2 km, an object is dropped from the aircraft. An aircraft is moving horizontally with a speed of 50 m/s. What is the time interval the object in air.ģ. The height of the object is the same when the time interval = 1 second and 3 seconds. G = acceleration due to gravity = 10 m/s 2Ģ. V oy = the initial velocity at the horizontal direction = 10√3 m/s V ty = the final velocity in the vertical direction = the final velocity at the highest point = 0 m/s The time interval to reach the maximum height, calculated using this equation : The initial velocity at the vertical direction (y axis) : The initial velocity at the horizontal direction (x axis) : Wanted : The time interval to reach the maximum height The initial velocity of bullet (v o) = 20 m/sĪcceleration due to gravity (g) = 10 m s –2 What is the time interval to reach the maximum height? A bullet fired a t an angle θ = 60 o with a velocity of 20 m/s.
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